4x^2+58x-37=0

Solution for 4x^2+58x-37=0 equation:

4x^2+58x-37=0

a = 4; b = 58; c = -37;
Δ = b2-4ac
Δ = 582-4·4·(-37)
Δ = 3956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3956}=\sqrt{4*989}=\sqrt{4}*\sqrt{989}=2\sqrt{989}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2\sqrt{989}}{2*4}=\frac{-58-2\sqrt{989}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2\sqrt{989}}{2*4}=\frac{-58+2\sqrt{989}}{8}
$